Math, asked by Vignan2173, 1 year ago

If alpha and beta are the zeroes of the equation 6x^2 + x - 2 = 0. Find 1/alpha + 1/beta

Answers

Answered by Anonymous
1

Answer:


Step-by-step explanation:

Here is your answer

1/2

Hope it helps



Answered by mdehtasham165
1

P(x) = 6x^2 + x - 2 = 0


Sum of alpha + bita = - 1/ 6

Product of alpha × bita = - 2/6

ATQ

1/ Alpha + 1/ bita

= bita + alpha ÷ alpha × bita

= -1/6 ÷ -2/6

= -1/6 × 6/ -2

= -1 ÷ -2

= 1/2

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