Question

if alpha and beta are the zeroes of the equation 6x²+x-2=0 find alpha/beta+beta/alpha​

Answer 1

Answer:

hope this is correct and helps you.

Answer 2

Let f(x) = 6x^2 + x - 2

Then, f(x) = x^2 +4x - 3x - 12

= x(x+4) - 3(x+4)

= (x -3)(x+4)

Therefore, the zeroes of f(x) are alpha = 3 and beta = -4

Then,

$\frac{ \alpha }{ \beta } + \frac{ \beta }{ \alpha } = \frac{3}{ -4 } + \frac{ -4 }{3} \\ = \frac{25}{-12} = \frac{-25}{12}$

HOPE THIS COULD HELP!!!