Question

If alpha and beta are the zeroes of the equation 6x2+x−2 then find 1/alpha+1/beta

Answer 1

Answer:

हद्ब्रह्नकगन्सगज कग्गुह्स्फुबक्सतुवकडूज

Answer 2

Answer:

Consider the given equation.

6x2+x−2=06x2+x−2=0           …….. (1)

Since, α,βα,β are roots of given equation.

So,

α+β=−ba=−16α+β=−ba=−16

αβ=ca=−26=−13αβ=ca=−26=−13

Since,

=αβ+βα=αβ+βα

=α2+β2αβ=α2+β2αβ

=(α+β)2−2αβαβ=(α+β)2−2αβαβ

=(−16)2−2×−13−13=(−16)2−2×−13−13 =\dfrac{{{\left( -\dfrac{1}{6} \right)}^{2}}-2\times -\dfrac{1}{3}}{-\dfrac{1}{3}}

=136+23−13=136+23−13

=1+2436−13=1+2436−13

=−2512

Hence, the value is −2512−2512.