Math, asked by unknown6554, 9 months ago

if alpha and beta are the zeroes of the polynomial 2x^2-3x-4. Form a quadratic polynomial whose zeroes are 1/alpha^2 and 1/beta^2​

Answers

Answered by Anonymous
9

Answer:

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Step-by-step explanation:

Alpha + beeta=-b/a

=3/2

Alphabeeta=c/a

=1/2

3alpha +3beeta=3(alpha+beeta)

=3×3/2=9/2=-b/a

3alpha×3beeta=9alphabeeta=9×1/2

=9/2=c/a

a=2 b=-9 c=9

Therefore quadratic polynomial= 2xsquare-9x+9

Thanks ❤

Answered by ramapprakashkushwaha
2

Answer

4x²+3x-2

Explanation

We have 2x^2-3x-4 whose roots are α and β.

By putting roots of new equation as 1/α and 1/β and solving as shown in figure.

Attachments:
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