if alpha and beta are the zeroes of the polynomial 2x^2-3x-4. Form a quadratic polynomial whose zeroes are 1/alpha^2 and 1/beta^2
Answers
Answered by
9
Answer:
Step-by-step explanation:
Alpha + beeta=-b/a
=3/2
Alphabeeta=c/a
=1/2
3alpha +3beeta=3(alpha+beeta)
=3×3/2=9/2=-b/a
3alpha×3beeta=9alphabeeta=9×1/2
=9/2=c/a
a=2 b=-9 c=9
Therefore quadratic polynomial= 2xsquare-9x+9
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Answered by
2
Answer
4x²+3x-2
Explanation
We have 2x^2-3x-4 whose roots are α and β.
By putting roots of new equation as 1/α and 1/β and solving as shown in figure.
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