If alpha and beta are the zeroes of the polynomial 2x^2-4x+5 find the value of 1/alpha+1/beta
Answers
Answered by
2
Hey
Here is your answer,
2x^2 - 4x + 5=0
Sum of zeroes = -b/a
Alpha + beta = 4/2
= 2
Product of zeroes = c/a
Alpha x beta = 5/2
To find:
=1/alpha+1/beta
=Alpha + beta /alpha x beta
=2/ 5/2
=2 x 2/5
=4/5
Hope it helps you!
Here is your answer,
2x^2 - 4x + 5=0
Sum of zeroes = -b/a
Alpha + beta = 4/2
= 2
Product of zeroes = c/a
Alpha x beta = 5/2
To find:
=1/alpha+1/beta
=Alpha + beta /alpha x beta
=2/ 5/2
=2 x 2/5
=4/5
Hope it helps you!
Answered by
0
Heyaa user!!!
-----------------------------------------------------
Here's your answer :-
The given equation is :-
2x²-4x+5..........
Here, a=2,b=-4,c=5
Now,
Since it is given that alpha and beta are the two zeroes of the polynomial. So, by formula we have :-
(alpha +beta) =-b/a=4/2=2. ............(i)
(alpha *beta) =c/a=5/2. .............(ii)
Now,
we have to find :-
1/alpha+1/beta
=(beta +Alfa) / alpha * beta
Now, putting values of eq (i) and (ii) , we get :-
2*2/5
=4/5
So, 4/5 is your answer!!!!
Hope this helps!!!
If there's any kind of doubt ,do lemme know!!!
Mark it as brinliest if u found it worthy....
Good luck :-)
-----------------------------------------------------
Here's your answer :-
The given equation is :-
2x²-4x+5..........
Here, a=2,b=-4,c=5
Now,
Since it is given that alpha and beta are the two zeroes of the polynomial. So, by formula we have :-
(alpha +beta) =-b/a=4/2=2. ............(i)
(alpha *beta) =c/a=5/2. .............(ii)
Now,
we have to find :-
1/alpha+1/beta
=(beta +Alfa) / alpha * beta
Now, putting values of eq (i) and (ii) , we get :-
2*2/5
=4/5
So, 4/5 is your answer!!!!
Hope this helps!!!
If there's any kind of doubt ,do lemme know!!!
Mark it as brinliest if u found it worthy....
Good luck :-)
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