Question

if alpha and beta are the zeroes of the polynomial 2x^2-7x+3,then find the value of alpha^2+beta^2.​

Answer 1

Step-by-step explanation:

First find the zeros of the equation by equating it to zero

We get values as x=6,1

which are alpha, beta

I.e,6^2+1^2=37

2x^2-7x+3=0

=> 2x^2-x-6x+3

=>(x-6)×(x-1)

Answer 2

Answer:

37/4

Step-by-step explanation:

$\alpha + \beta = \frac{7}{2}$

$\alpha ^{2} + { \beta }^{2} = ( \alpha + \beta )^{2} - 2 \alpha \beta$

and

$\alpha \beta = \frac{3}{2}$

so (7/2)²-2(3/2)

49/4-3

37/4

so the answer is 37/4