if alpha and beta are the zeroes of the polynomial 2x^2+7x+5 find the value of
1.alpha +beta+alpha×beta
2.1/alpha+1/beta
3.alpha/beta+beta/alpha
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Step-by-step explanation:
- alpha +beeta =-7/2
alpha ×beeta = 5/2
2. 1/alpha +1/beeta =
=(alpha +beeta) /alpha beeta
= -7/2 / 5/2
-7/5
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