Question

if alpha and beta are the zeroes of the polynomial 2x^2+x-6 then form a quadratic equation whose zeroes are 2 alpha and 2 beta​

Answer 1

Solution

2x²+x-6=0

=>x²+(x/2)-3=0

comparing the equations with

x²-(a+b)X+ab=0

now... where the roots are a and b

so...

(a+b)=1/2

and...

ab=-6

now the equations whose zeroes are 2a and 2b is....

=>x²-(2a+2b)x+(2a)(2b)=0

=>x²-2(a+b)x+4(ab)=0

=>x²-2(1/2)x+(-6)=0

=>x²-x-24=0

~~~~~Hope this helps u~~~~~~