Math, asked by chpsanju, 1 month ago

If alpha and beta are the zeroes of the polynomial 2x2 -7x+5 . find the value of 1/alpha + 1/beta​

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Answered by uttamughade2015
2

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Answered by ajay8949
0

 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: 2 {x}^{2}   - 7x + 5 = 0

 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: ( \alpha \:  \:  +  \beta) =  -  \frac{b}{a} =  \frac{7}{2}

  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \alpha \beta =   \frac{c}{a}  =  \frac{5}{2}

 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: value \: of \:  \frac{1}{ \alpha}  +  \frac{1}{ \beta}

 =  > \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \frac{ \beta +  \alpha}{  \alpha \beta}

 =  > \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \frac{ \frac{7}{2} }{ \frac{5}{2} }  \\

 =  >   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \frac{7}{2}   \times  \frac{2}{5}

 =  >    \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \pink{\sf {\frac{7}{5}} }

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