Question

If alpha and beta are the zeroes of the polynomial 3x^2+2Kx-6 then find alpha-beta

Answer 1

Answer:

3x^2+2kx-6

so, a=3. b=2k. c=-6

then, alpha+beta = -b/a

alpha×beta=c/a

alpha+beta=-2k/3

alpha×beta=-6/3

=-2

alpha-beta=-(alpha+beta)

=-(-2k/3)

so, the answer is

2k/3

i hope u understand

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Answer 2

Answer:

(1+α)(1+β)

(1−α)(1−β)

(1+α+β=αβ)

(1−α−β+αβ)

(

1+(α+β)+αβ

1−(α+β)+αβ

)

⎣

⎢

⎢

⎡

1−

3

2

+

3

1

1+

3

2

+

3

1

⎦

⎥

⎥

⎤

[

2

2×3

]=3

=

(1+α+β+αβ)

(1−α)(1+β)+(1−β)(1+α)

=

3

2

1+β−α−αβ+1+α−β−αβ

=

2

3(2−2αβ)

=3(1−αβ)

=3(1−

3

1

)

=2