if alpha and beta are the zeroes of the polynomial 6x^2 -7x -3 find the value of alpha/beta + beta/alpha
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6x^2 -7x -3 =0
6x^2 -9x +2x -3 =0
3x(2x-3) +1(2x-3) 0
(2x-3)(3x+1) =0
alpha is 3/2
beta is -1/3
alpha/beta +beta /alpha
(3/2)/(-1/3) + (-1/3)/(3/2)
-9/2 -9/2
-85 / 18
i think it's-85/18
6x^2 -9x +2x -3 =0
3x(2x-3) +1(2x-3) 0
(2x-3)(3x+1) =0
alpha is 3/2
beta is -1/3
alpha/beta +beta /alpha
(3/2)/(-1/3) + (-1/3)/(3/2)
-9/2 -9/2
-85 / 18
i think it's-85/18
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Actually i wanted it without splitting the middle term
oj ok
oh
how about this method
in the picture
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