If alpha and beta are the zeroes of the polynomial ax square+bx +c then find the values of 1 by alpha + 1 by beta
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Answer :
The given polynomial is f(x) = ax² + bx + c
Since α and β are the zeroes of f(x),
α + β = - b/a .....(i)
αβ = c/a .....(ii)
Now, 1/α + 1/β
= (β + α)/(αβ)
= (- b/a)/(c/a)
= - b/c
⇒ 1/α + 1/β = - b/c
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