Question

if alpha and beta are the zeroes of the polynomial f(x)=2x^2-7x+3.find alpha^3+beta^3​

Answer 1

2x²-7x+3=0

2x²-x-6x+3=0

x(2x-1)-3(2x-1)=0

(x-3)(2x-1) =0

x=1/2,3

alpha=1/2

beta=3

Therefore,

(alpha)³+(beta) ³

(1/2)³+(3)³

1/8+27

217/8

hope it helps

:-)