If alpha and beta are the zeroes of the polynomial f (X)=2x^2+5x+k, satisfying the relation alpha^2+ beta^2+alpha* beta=21/4. Find the value of k
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Answer:
k=2
Step-by-step explanation:
alpha^2+beta^2+alpha.beta=21/4
(alpha+beta)^2-2alpha.beta+alpha.beta=21/4
(-b/a)^2-(c/a)=21/4
(-5/2)^2-(k/2)=21/4
25/4-k/2=21/4
25-2k/4=21/4
25-2k=21
k=2
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