Question

If alpha and beta are the zeroes of the polynomial for p(x)= 4 x^2 + 3x + 7, then (1/alpha + 1/beta) is 7/3 -7/3 3/7 -3/7

Answer 1

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Here's your answer

Since α and β are the zeroes of p(x) = 4x²+3x+7 ,

we know that

α+β = -b/a

αβ = c/a

In this case,

a = 4

b = 3

c = 7

Hence

α+β = -3/4

αβ = 7/4

1/α + 1/β

= (α+β)/αβ

= (-3/4) / (7/4)

= -3/7

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