Question

If alpha and beta are the zeroes of the polynomial p(x)=5x²+x+1 then find the sum of their reciprocals that is 1/alpha + 1/beta

Answer 1

Given:-

๛α and β are the zeros of p(x)

๛p(x)=5x²+x+1

$\rule{200}{1}$

To Find:-

✪The Sum of their Reciprocals $\frac{1}{ \alpha}$+$\frac{1}{\beta}$

$\rule{200}{1}$

AnsWer:-

☞Sum of Reciprocals is→ $\frac{1}{25}$

$\rule{200}{1}$

↝α+β=$\frac{-b}{a}$

↝α+β=$\frac{-(1)}{5}$

↝α+β=-⅕

↝αβ=$\frac{c}{a}$

↝αβ=$\frac{1}{5}$

★Cross Multiplying Sum of Reciprocals★

➜$\frac{ \alpha + \beta}{\alpha \times \beta}$

♦Putting The Values♦

↝⅕÷⅕

↝$\frac{1 \times 1}{5 \times 5}$

↝$\frac{1}{25}$

Answer 2

Answer:

it's not 1/25 it is -1 .

check proparly