If alpha and beta are the zeroes of the polynomial such that alpha plus beta is equa to24 and alpha minus beta is equal to 8, find a quadratic polynomial having alpha and beta as its zeros
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first substitute alpha and beta you will get alpha as 16 and beta as 128
now alpha plus beta = -b/a
and alphabeta=128=c/a
so the required equation is x^2-24x+128
now alpha plus beta = -b/a
and alphabeta=128=c/a
so the required equation is x^2-24x+128
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