Question

If alpha and beta are the zeroes of the polynomial
${x}^{2} - 2x + 3$
, then value of alpha
$\frac{1}{alpha} + \frac{1}{beta}$
Is

Answer 1

HELLO.....FRIEND!!

THE ANSWER IS HERE,

$= > \: \frac{1}{ \alpha } + \frac{1}{ \beta }$

$= > \: \frac{ \alpha + \beta }{ \alpha \beta }$

Sum of the zeroes,

$= > \: \alpha + \beta = \frac{ - b}{a}$

$= > \: \frac{ - ( - 2)}{1}$

=> 2.

Product of zeroes,

$= > \: \alpha \beta = \frac{c}{a}$
$= > \: \frac{3}{1}$

=>3.

So,

$= > \: \frac{ \alpha + \beta }{ \alpha \beta } = \frac{2}{3}$


:-)Hope it helps u.

Answer 2

Hi Friend !!!

==================

x²-2x+3 = 0

1/α+1/β = α + β /αβ

= -b/a ÷ c/a

= -b/c

= - -2/3

= 2/3

Hope it helps u:-)