If alpha and beta are the zeroes of the polynomial x*2-5x+3(k-1)and alpha-beta=11 and beta =11 find k
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Step-by-step explanation:
alpha+beta=-(-5)/1 i.e. 5.....(1)
alpha-beta=11 ( Given) .......(2)
By adding (1) & (2) we get
2*alpha= 11+5 = 16
--->alpha =8
And from (1)
Beta = 5-alpha
= 5-8, by putting alpha=8
=-3
Again we know product of alpha and beta is 3(k-1)
i.e. 3(k-1)=8*(-3)
---> k-1=-8
And k =-7
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