Question

if alpha and beta are the zeroes of the polynomial x^2 - 6x + 8, then the value of alpha^3 + beta^3 is​

Answer 1

Answer:

20

Step-by-step explanation:

comparing with ax^2+bx+c

a=1 b= -6 c= 8

alpha +beta = -b /a

= - (-6)/1

=6

alpha x beta = c/a

=8/1

8

alpha^3 +beta ^3 =(alpha +beta)^2 - 2alpha x beta

=(6)^2 - 2 x 8

= 36-16

=20