If alpha and beta are the zeroes of the polynomial x^2+8x+6 . From the polynomial whose zeroes are A) 1/alpha ^2 and 1/ beta^2 B) alpha - beta, alpha + beta
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If alpha and beta are the zeroes of the polynomial x^2+5x+6 . From the polynomial whose zeroes are
- 1/alpha ^2 and 1/ beta^2
- alpha - beta
- alpha + beta
Replacing
Given
A polynomial x²+8x+6
whose Zeroes are A and B
To Find
- 1/A²+ 1/B²
- A-B
- A+B
Solution
x²+5x+6
=>x²+3x+2x+6
=>x(X+3)+2(X+3)
=>(X+2) (X+3)
Zeroes are X=-2,-3
Now
A= -2
B= -3
we know that
- A+B= -b/a
- A+B= -5
- AB = c/a
- =6
Now
1/A²+ 1/B²
=>A²+B²/A²B²
=>-5/36
- A-B = -2 - (-3)
= 1
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