Question

If alpha and Beta are the zeroes of the polynomial x^2-p(x+1)-c, then find the value of (alpha +1)(beta+1)= 1-c and also show that, alpha square+2 alpha+1/alpha square+2 alpha x + beta square+2beta+1/beta square + 2 beta +c =1​

Answer 1

Answer:

and plus B the whole score is equal to square + 2 a b plus b square is equal to

Answer 2

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$\large\green{\mid{\fbox{\tt{Ꭲօ թɾօѵҽ}}\mid}}$

$\frac{sinθ}{1+cosθ}+\frac{1+cosθ}{sinθ}=2cosecθ$

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$\large\pink{\mid{\fbox{\tt{ᏞᎻร}}\mid}}$=

$⟹\sf\bold{\blue{\frac{sinθ}{1+cosθ}+\frac{1+cosθ}{sinθ}}}$

$⟹\sf\bold{\blue{\frac{sin²+(1+cosθ)²}{(1+cosθ)sinθ}}}$

$⟹\sf\bold{\blue{\frac{sin²+1+cos²θ+2cosθ}{(1+cosθ)sinθ}}}$

$⟹\sf\bold{\blue{\frac{sin²+cos²θ+1+2cosθ}{(1+cosθ)sinθ}}}$

$⟹\sf\bold{\blue{\frac{2+2cosθ}{(1+cosθ)sinθ}}}$

$⟹\sf\bold{\blue{\frac{2(1+cosθ)}{(1+cosθ)sinθ}}}$

$⟹\sf\bold{\blue{\frac{2}{sinθ}}}$

$⟹\large\pink{\mid{\fbox{\tt{2.coseθ}}\mid}}$

$\large\pink{\mid{\fbox{\tt{ᏞᎻร=ƦᎻร}}\mid}}$

✶⊶⊷⊶⊷❍ ❥ ❍⊶⊷⊶⊷✶

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⠀⠀⠀ $\large\green{\mid{\fbox{\tt{❥ϐℓυєᴇყεร}}\mid}}$

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