If alpha and beta are the zeroes of the polynomial x^2+px+q, find the value of (alpha/beta + 2)(beta/alpha + 2)
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Answer:
5 - 2(p/q)
Step-by-step explanation:
alpha + beta = -p -----------(1)
(alpha)(beta) = q --------------(2)
(alpha + beta)/(alpha)(beta) = -p/q --------- (3)
Simplifying the given expression
(alpha/beta + 2)(beta/alpha + 2)
= alpha/beta*beta/alpha + 2*alpha/beta + 2*beta/alpha +4
=1+ 2*alpha/beta + 2*beta/alpha + 4
= 5 + 2(alpha + beta)/(alpha)(beta)
= 5 +2 (-p/q) (From (3) )
= 5 - 2(p/q)
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