if alpha and beta are the zeroes of the polynomial x2-5x+k, such that alpha-beta=1, find the value
plz solve by discriminate method
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Answer:
x²-5x+k
α+β=5--eq1
α-β=1(given)--eq2
Add eq1 and eq2, we get
2β=4
β=4/2
β=2
Substitute β=2 in eq2
α-β=1
α-2=1
α=1+2
α=3
αβ=k--eq3
αβ=3×2=6(given)--eq4
From eq1 and eq2, we get
k=6
Or
x²-5x+k
a=1, b=(-5), c=k
Discriminant=0
b²-4ac=0
(-5)²-4(1)(k)=0
25-4k=0
(-4k)=(-25)
4k=25
k=25/4
k=6.25
I have solved it by both the methods.
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