Question

If alpha and beta are the zeroes of the polynomial x2+6x+9=0,then form a polynomial whoes zeroes are-alpha and -beta

Answer 1

Answer:

Step-by-step explanation:

x^2 + 6x + 9 = 0

(x + 3)^2 = 0

alpha = beta = -3

- alpha = - beta = 3

(x -3)(x -3) = 0

x^2 - 6x + 9 = 0

Answer 2

Answer:

x2-6x+9=0

Step-by-step explanation:

Alpha+beta=-b/a=-6 and (alpha)x(beta)=c/a=9

therefore, -Alpha-beta=-(Alpha+beta)= -(-6)=6=-B/A (i.e., B/A=-6)

                 (-alpha)x(-beta)=(alpha)x(beta)=9= C/A

the quadartic equation whose zeros are (-alpha)&(-beta) is

x^2+(B/A)x+(C/A)=0

x2-6x+9=0