Math, asked by gaurisareen14, 11 months ago

If alpha and beta are the zeroes of the polynomial x2 -p(x+1) -c . Find the Value of (alpha+1) (beta+1)

Answers

Answered by Anonymous
1
Heya!!

FOR A GENERAL QUADRATIC EQUATION

ax² + bx + c = 0

Alfa + Beta = -b/a

And

Alfa × Beta = c/a

_______________________________

Qno.1

Exp:-

( Alfa + 1 ) × ( Beta + 1 ) =

Alfa × Beta + ( Alfa + Beta ) + 1

_______________________________

Alfa + Beta = p. And Alfa × Beta = (-p-c)

=>

( -p - c ) + ( p ) + 1

=>

1 - c

So, ( Alfa + 1 ) × ( Beta + 1 ) = ( 1 - c )
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