If alpha and beta are the zeroes of the polynomial x2 -p(x+1) -c . Find the Value of (alpha+1) (beta+1)
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Heya!!
FOR A GENERAL QUADRATIC EQUATION
ax² + bx + c = 0
Alfa + Beta = -b/a
And
Alfa × Beta = c/a
_______________________________
Qno.1
Exp:-
( Alfa + 1 ) × ( Beta + 1 ) =
Alfa × Beta + ( Alfa + Beta ) + 1
_______________________________
Alfa + Beta = p. And Alfa × Beta = (-p-c)
=>
( -p - c ) + ( p ) + 1
=>
1 - c
So, ( Alfa + 1 ) × ( Beta + 1 ) = ( 1 - c )
FOR A GENERAL QUADRATIC EQUATION
ax² + bx + c = 0
Alfa + Beta = -b/a
And
Alfa × Beta = c/a
_______________________________
Qno.1
Exp:-
( Alfa + 1 ) × ( Beta + 1 ) =
Alfa × Beta + ( Alfa + Beta ) + 1
_______________________________
Alfa + Beta = p. And Alfa × Beta = (-p-c)
=>
( -p - c ) + ( p ) + 1
=>
1 - c
So, ( Alfa + 1 ) × ( Beta + 1 ) = ( 1 - c )
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