if alpha and beta are the zeroes of the quadratic polynomial p(x)=x2+5x-6,find the polynomial whose zeroes are 2aplha + 1 and 2beta + 1
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Solution :
The given polynomial is
f (x) = x² - 5x + 6
⇒ f (x) = x² - 3x - 2x + 6
⇒ f (x) = x (x - 3) - 2 (x - 3)
⇒ f (x) = (x - 3) (x - 2)
Let, α = 3 and β = 2 [ ATQ ]
To find : the polynomial whose zeroes are (2α + 1) and (2β + 1).
Now, 2α + 1 = (2 * 3) + 1 = 7
and 2β + 1 = (2 * 2) + 1 = 5
∴ the required polynomial is
g (x) = {x - (2α + 1)} {x - (2β + 1)}
⇒ g (x) = (x - 7) (x - 5)
⇒ g (x) = x² - 7x - 5x + 35
⇒ g (x) = x² - 12x + 35
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