If alpha and beta are the zeroes of the quadratic polynomial f(x) = x2 - px + q, prove that alpha2/beta2 + beta2/alpha2= p4/q2 - 4p2/q + 2?
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Answered by
0
Answer:
have, f(x)=x
2
−px+q
Since α and β are zeros of the given polynomial, then
α+β=
coefficient of x
2
−coefficient of x
=
1
−(−p)
=p ...(i)
Also, αβ=
coefficient of x
2
−constant term
=
1
q
=q ...(ii)
Now,
β
2
α
2
+
α
2
β
2
=
(αβ)
2
α
4
+β
4
=
(αβ)
2
(α
2
+β
2
)
2
−2α
2
β
2
=
(αβ)
2
[(α+β)
2
−2αβ]
2
−2
Answered by
3
Step-by-step explanation:
sin square theta + cos square theta =1
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