if alpha and beta are the zeroes of the quadratic polynomial p(x)=x2-5x+6,find the value of alpha2 +beta2,aplha3+beta3
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Answer:
x² - 5x + 6
⇒ a = 1; b = -5; c = 6
Finding the zeroes of the polynomial
⇒ = -b/a
⇒ = -(-5)/1
⇒ = 5 ------------> eq. 1
⇒ = c/a
⇒ = 6/1
⇒ = 6
∴ The zeroes are 5 and 6.
(5)²×(5)³
25×125
3125
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