If alpha and beta are the zeroes of the quadratic polynomial f(x)=x^2-x-4,find the value of 1/alpha+1/beta-alphabeta
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3
Answer:
15/4
Step-by-step explanation:
to find: 1/α+1/β-αβ
x²-x-4
ax²-bx+c
α+β=-b/a
αβ=c/a
α+β= -(-1)/1= 1
αβ= -4/1= -4
now,
1/α+1/β-αβ= (α+β)/αβ - αβ
1/-4 - (-4)
-1/4 + 4
(-1+16)/4
15/4
mohit9894:
plzz expain step by step
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