Question

If alpha and beta are the zeroes of the *quadratic polynomial* 2x^2-3x-5, form a quadratic polynomial whose zeroes are:- alpha/(alpha^2+beta^2) ; beta/(alpha^2+beta^2).

Answer 1

Answer:

zeroes of the polynomial are

-1,2.5

so -1²/-1²+2.5² = 1/7.25

6.25/1+6.25= 6.25/7.25

so polynomial is,

(x-6.25/7.25)(x-1/7.25)

PLS MARK IT BRAINLIEST

I BEG U

Answer 2

2x^2+2x-5x-5=0

2x(x+1)+5(x+1)=0

(x+1)(2x+5)=0

x=-1. x=-5/2

-1/(1+25/4)= -1/(29/4)= -4/29

-5/2/(1+25/4) =-5/2/(29/4) =-10/29