Question

If alpha and beta are the zeroes of the quadratic polynomial p(x)=ax2+bx+c then evaluate alpha ^2betq+alpha beta^2

Answer 1

Answer:

p(x)=ax2+bx+c

α+β=-b/a

αβ=c/a

α^2β+αβ^2=αβ(α+β)

=c/a(-b/a)

=(-bc)/(a^2)

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Answer 2

If alpha and beta are the zeroes of the quadratic polynomial p(x)=ax2+bx+c then evaluate alpha ^2betq+alpha beta^2

SOLUTION

p(x) = ax² + bx + c

alpha + beta = - b/a

alpha * beta = c / a

alpha² beta+alpha beta²

alpha*beta(alpha + beta)

c/a * -b/a

-bc/a²