Question

if alpha and beta are the zeroes of the quadratic polynonial p(y) = 5y-7+1 find the value of 1/alpha + 1/beta

Answer 1

given= 5y^2-7y+1

here,

a= 5, b= -7 and c= 1

we know that,

sum of zeroes= -b/a

$\alpha + \beta = \frac{7}{5}$
_______________(1)

also,


products of zeroes= c/a
$\alpha \beta = \frac{1}{5}$
_______________(2)

now,


$\frac{1}{ \alpha } + \frac{1}{ \beta } \\ \\ = \frac{ \beta + \alpha }{ \beta \alpha }$
from 1 and 2 ,

$\frac{7}{5} \div \frac{1}{5} \\ \\ = \frac{7}{5} \times {5} \\ \\ = 7$

Answer 2

Answer:

Step-by-step explanation: