Math, asked by royankitachowdhury24, 6 months ago

If alpha and beta are the zeroes of thr polynomial f(x)=x^2-5x+k S.t. alpha × beta=1 , find the value of k.​

Answers

Answered by kaushik05
28

Given:

F(x) = x²-5x+k .

 \:  \alpha  \beta  = 1

To find :

• The value of k

Solution:

•F(x)= x²-5x+k

Here ,

• a = 1

• b= -5

•c= k .

As we know that:

 \star \bold{  \alpha  \beta  =  \frac{c}{a} } \\

 \implies \:  \alpha  \beta  = 1 \\  \\  \implies \:  \frac{c}{a}  = 1 \\  \\  \implies \:  \frac{k}{1}  = 1 \\  \\  \implies \: k = 1

Hence ,the value of k is 1.

Answered by Anonymous
13

Answer:

f{x}= x^2-5x+k

alpha beta = 1

c/a= 1

k/1= 1

k=1

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