Question

If alpha and beta are the zeroes of x^(2)-3x+2 find the value of alpha^(3)+beta^(3) ?​

Answer 1

Answer:

180

Step-by-step explanation:

Given $x^{2} -3x +2$.

The formula for α³+β³ is (α+β)(α²+β²-αβ)

We know that α+β = -b/a and αβ = c/a

so α+β = 6

αβ = 2

Now, α²+β² = (α+β)² - 2αβ

                    = 6² - 2x2

                    = 32

By applying all the answers we got, we can find the final answer.

α³+β³ = 6 (32 - 2)

          = 6x30

          = 180

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