If alpha and beta are the zeroes of x^2+7x+12,then find the value of 1/alpha + 1/beta - 2alpha×beta
Answers
Answered by
8
Hey Friends!!
Here is your answer↓
Let alpha=@
and beta=ß.
Since,@ and ß are zeros of polynomial.
→x²+7x+12=0
→x²+4x+3x+12=0
→x(x+4)+3(x+4)=0
→ (x+4)(x+3).=0
→x+4=0;x=-4.←@.
→x+3=0;x=-3←ß.
A/Q.
→ 1/@+1/ß-2@×ß.
→ 1/-4+1/-3 -2(-4)×(-3).
→ -7/12 - (-24).
→ -7/12+24.
→ 281/12.
☺☺☺ Hope it is helpful for you ✌✌✌.
Here is your answer↓
Let alpha=@
and beta=ß.
Since,@ and ß are zeros of polynomial.
→x²+7x+12=0
→x²+4x+3x+12=0
→x(x+4)+3(x+4)=0
→ (x+4)(x+3).=0
→x+4=0;x=-4.←@.
→x+3=0;x=-3←ß.
A/Q.
→ 1/@+1/ß-2@×ß.
→ 1/-4+1/-3 -2(-4)×(-3).
→ -7/12 - (-24).
→ -7/12+24.
→ 281/12.
☺☺☺ Hope it is helpful for you ✌✌✌.
Answered by
3
S = -7 p = 12
{( Alpha + beta) / alpha × beta} -2 alpha × beta
-7/12 - 2×12
-7 /12 - 24 = -281/12...ANSWER....
Thank u★★★
#ckc
{( Alpha + beta) / alpha × beta} -2 alpha × beta
-7/12 - 2×12
-7 /12 - 24 = -281/12...ANSWER....
Thank u★★★
#ckc
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