Question

if alpha and beta are the zeroes of x^2-x-2, form a quadratic polynomial whose zeroes are 2alpha+1 and 2beta+1​

Answer 1

Answer:

Step-by-step explanation:

P(x) = x^2 - x-2

0 = x^2 -(2-1) x -2

0= x^2 -2x+x -2

0= x(x-2) +1(x-2)

0= (x+1) (x-2)

x+1 = 0

x=-1

x-2 = 0

x= 2

= -1

=5

General form of quadratic equation:-

p(x) = x^2 -(alpha+beta)x + alpha × beta

So , the new equation is :-

0= x^2 -(-1+5)x + (-1)×5

0= x^2 -(4)x -5

0=x^2 -4x -5

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