if alpha and beta are the zeroes of x square+5x+6 if two zeroes are 2 and 3
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x² + 5x +6=0
=> x² + 2x + 3x+ 6 =0
=> x(x+2 )+3(x+2)=0
=>(x+3) or(x+2)=0
x= -2 or x= -3
=> x² + 2x + 3x+ 6 =0
=> x(x+2 )+3(x+2)=0
=>(x+3) or(x+2)=0
x= -2 or x= -3
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