if alpha and beta are the zeroes of x²-3x+1 . then alpha power 2014 +alpha power 2016+beta power 2014+beta power 2016/alpha 2015+beta power 2015
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Answer:
Step-by-step explanation:
α,β are roots of x
2
−3x+1=0
∴α
2
−3α+1=0 - (1) ⇒α
2
+1=3α
β
2
−3β+1=0 - (2) ⇒β
2
+1=3β
=
α
2015
+β
2015
α
2014
+β
2014
+α
2016
+β
2016
=
α
2015
+β
2015
α2014(1+α
2
)+β
2014
(1+β
2
)
=
α
2015
+β
2015
α
2014
(3α)+β
2014
(3β)
= 3
pls mark brainliest
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