Question

if alpha and beta are the zeroes of x2+7x+12 find the value of 1/alpha + 1/beta +2alpha.beta​

Answer 1

Answer:

281/12

Step-by-step explanation:

Given,

x^2+7x+12=0

and alpha and beta are the roots

Therefore,

alpha+beta= -7

alpha×beta=12

now,

= 1/alpha + 1/beta +2alpha.beta

= ( alpha+beta)/alpha.beta +2alpha.beta

= {alpha+beta+2(alpha.beta)^2}/alpha.beta

= {-7+2(12)^2}/12

=281/12

Hope it helps