If alpha and beta are the zeros of 4x2-4x+1,find alpha and beta
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Answered by
3
Hey
Here is your answer,
4x2-4x+1 =0
4x^2 -2x -2x+1=0
2x(2x-1)-1(2x-1)=0
(2x -1)(2x -1)=0
2x -1=0
X=1/2
2x -1=0
X=1/2
Therefore, the zeroes are 1/2 and 1/2 .
Hope it helps you!
Here is your answer,
4x2-4x+1 =0
4x^2 -2x -2x+1=0
2x(2x-1)-1(2x-1)=0
(2x -1)(2x -1)=0
2x -1=0
X=1/2
2x -1=0
X=1/2
Therefore, the zeroes are 1/2 and 1/2 .
Hope it helps you!
Answered by
2
Answer :
Now, 4x² - 4x + 1
= (2x)² - (2 × 2x × 1) + 1²
= (2x - 1)²
= (2x - 1)(2x - 1)
So, the required zeroes of the polynomial be
1/2 and 1/2
Hence, α = β = 1/2
#MarkAsBrainliest
Now, 4x² - 4x + 1
= (2x)² - (2 × 2x × 1) + 1²
= (2x - 1)²
= (2x - 1)(2x - 1)
So, the required zeroes of the polynomial be
1/2 and 1/2
Hence, α = β = 1/2
#MarkAsBrainliest
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