Math, asked by apurvasharma95571, 5 hours ago

if alpha and beta are the zeros of 5x^2-7x+2 then 1/alpha+1/beta= ? ​

Answers

Answered by muzamilpathan119
0

Answer:

eudleyusuu

Step-by-step explanation:

. togrrr er tyolo reyew to owe Errol yew

Answered by nana66
0

α + β = Sum of zeros

= -(coefficient of x)/(coefficient of x2) = 7/5

α β = Product of zeros

= (constant term)/(coefficient of x2) = 1/5

Now, (1/α + 1/β) = (α + β) / αβ = 7/5 x 5/1 = 7

Similar questions