if alpha and beta are the zeros of 5x^2-7x+2 then 1/alpha+1/beta= ?
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eudleyusuu
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α + β = Sum of zeros
= -(coefficient of x)/(coefficient of x2) = 7/5
α β = Product of zeros
= (constant term)/(coefficient of x2) = 1/5
Now, (1/α + 1/β) = (α + β) / αβ = 7/5 x 5/1 = 7
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