Math, asked by Jenilia, 1 year ago

if alpha and beta are the zeros of a polynomial 9y^2+12y+4, then find the value of alpha+beta+aloha*beta.

Answers

Answered by Jahnavidax
76
  P(x)=  9y²+12y+4
   Here, a=9,  b=12,   c=4
        ∴α+β=   -b/a
                = -12/9
                = -4/3
          α×β=  c/a
                  = 4/9

            Now, (α+β)+(α×β)
                    = -4/3 + 4/9
                     = -8/9

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Answered by Rajusingh45
26
Hey dear !!

___________________________

==> In the equation ,

p(x) = 9y² + 12y + 4

We have to find the value of α+β + αβ

We have ,

a = 9

b = 12

c = 4

We know that,

α + β = -b/a

= -12/9

= -4/3

Also,

αβ = c/a

= 4/9

A.T.Q

α + β + αβ

 = > \frac{ - 4}{3} + \frac{4}{9} \\ \\ = > \frac{ - 4}{3} \times \frac{3}{3} + \frac{4}{9} \times \frac{1}{1} \\ \\ = > \frac{ - 12}{9} + \frac{4}{9} \\ \\ = > \frac{ - 12 + 4}{9} \\ \\ = > \frac{ - 8}{9}
∴ The value of α+β + αβ => -8/9


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