if alpha and beta are the zeros of a polynomial x square - 5 x + k and alpha minus beta is equal to minus 1 find the value of k
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Given equation :- x² - 5x + k = 0
Where , a = 1 , b = - 5 , c = k
α and β are the zeros of the polynomial.
Then , Sum of the zeros ( α + β ) = c / a = k / 1 = k
And , Product of the zeros ( αβ ) = -b / a = - ( -5 ) / 1 = 5
Now given ,
α - β = - 1
( α - β )² = ( - 1 )² [ • Both sides square ]
α² - 2αβ + β² = 1 [ • Using identity , ( a - b )² = a² - 2ab + b² ]
( α² + β² ) - 2αβ = 1
( α + β )² - 2αβ - 2αβ = 1 [ • Using identity , a² + b² = ( a + b )² - 2ab ]
( k )² - 4 × 5 = 1 [ • Putting the values ]
k² - 20 = 1
k² = 1 + 20
k² = 21
k = √21 [ • Required Answer ]
vijverma:
pls explain the last step
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