Math, asked by Narindersaini488, 10 months ago

if alpha and beta are the zeros of a polynomial x square - 7 x + K such that Alpha minus beta is equal to 1 then find the value of k​


mahek2047: answer is 12
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Answers

Answered by Swarup1998
112

Answer : k = 12

Solution :

Given polynomial is

    f(x) = x² - 7x + k

Since α and β are the zeroes of f(x), by the relation between zeroes and coefficients, we get

    α + β = - (- 7/1) = 7

    αβ = k

Given, α - β = 1

Squaring both sides, we get

  (α - β)² = 1²

⇒ (α + β)² - 4αβ = 1

⇒ (- 7)² - 4k = 1

⇒ 49 - 4k = 1

⇒ 4k = 49 - 1 = 48

⇒ k = 48/4

k = 12


jayson222567: alpha-beta=dicriminant(D)/mod of a
jayson222567: D=b^2-4ac
jayson222567: 1=b^2-4ac/mod of a
jayson222567: 1=(7^2-4k)/1
jayson222567: -4k=-48
jayson222567: k=12
deepsen640: good answer
sakina78642: it can be done in much simpler way.... but still u did a gud job..truly appreciated!!!!
taibak32: very nice ans❤️
Avanish010: Brilliant Answer bro
Answered by suman682
50

K is 12.

K is 12.From the given quadratic equation, we can see that alpha + beta = 7. alpha - beta = 1 is given.

K is 12.From the given quadratic equation, we can see that alpha + beta = 7. alpha - beta = 1 is given.Let me use alpha as a and beta as b.

K is 12.From the given quadratic equation, we can see that alpha + beta = 7. alpha - beta = 1 is given.Let me use alpha as a and beta as b.(a+b)^2 -4ab = (a-b)^2.

K is 12.From the given quadratic equation, we can see that alpha + beta = 7. alpha - beta = 1 is given.Let me use alpha as a and beta as b.(a+b)^2 -4ab = (a-b)^2.Substituting a+b = 7, a-b = 1, we get

K is 12.From the given quadratic equation, we can see that alpha + beta = 7. alpha - beta = 1 is given.Let me use alpha as a and beta as b.(a+b)^2 -4ab = (a-b)^2.Substituting a+b = 7, a-b = 1, we get4ab = 48

K is 12.From the given quadratic equation, we can see that alpha + beta = 7. alpha - beta = 1 is given.Let me use alpha as a and beta as b.(a+b)^2 -4ab = (a-b)^2.Substituting a+b = 7, a-b

Let me use alpha as a and beta as b.

Let me use alpha as a and beta as b.(a+b)^2 -4ab = (a-b)^2.

Let me use alpha as a and beta as b.(a+b)^2 -4ab = (a-b)^2.Substituting a+b = 7, a-b = 1, we get

Let me use alpha as a and beta as b.(a+b)^2 -4ab = (a-b)^2.Substituting a+b = 7, a-b = 1, we get4ab = 48

Let me use alpha as a and beta as b.(a+b)^2 -4ab = (a-b)^2.Substituting a+b = 7, a-b = 1, we get4ab = 48ab = 12.

Let me use alpha as a and beta as b.(a+b)^2 -4ab = (a-b)^2.Substituting a+b = 7, a-b = 1, we get4ab = 48ab = 12.Therefore we can clearly see that k = 12


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