if alpha and beta are the zeros of a quadratic polynomial f of x = 2 x square - 5 x + 1 find the polynomial whose zeros are 2 alpha + 3 Beta and 3 alpha + 2 beta. ( Without the concept of 'i')
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Answered by
3
Heya
_______________________________
Required quadratic equation in x is
x² - ( 5× ( Alfa + Beta ) ) + 6( Alfa² + Beta² ) + 13 Alfa × Beta
=>
Alfa + Beta = 5/2
And
Alfa × Beta = 1/2
=>
x² - ( 5× ( 5/2 )x + 6 ( 25/4 ) +11 ( 1/2)
=>
x² - (25/2 )x + 47×3/2
OR
x² -25x + 141=0
_______________________________
Required quadratic equation in x is
x² - ( 5× ( Alfa + Beta ) ) + 6( Alfa² + Beta² ) + 13 Alfa × Beta
=>
Alfa + Beta = 5/2
And
Alfa × Beta = 1/2
=>
x² - ( 5× ( 5/2 )x + 6 ( 25/4 ) +11 ( 1/2)
=>
x² - (25/2 )x + 47×3/2
OR
x² -25x + 141=0
Answered by
1
It could help you.
And it can be solve more
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rajiv08:
thanks
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