If alpha and beta are the zeros of f(x) = x^2+kx+45 such that their squared difference is 144 , find the value of k.
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Hey
Here is your answer,
x^2+kx+45=0
Sum of zeroes = -b/a
Alpha + beta = -k
Product of zeroes = c/a
Alpha x beta = 45
In the given eq. x2+kx+45 in the form of ax2 + bx + c
We get a = 1, b= k and c = 45
Replacing values,
(-k/1)2 – 4* (45/1) = 144
=> k2 – 180 = 144
=> k2 = 324
=> k = 18
Hope it helps you!
Here is your answer,
x^2+kx+45=0
Sum of zeroes = -b/a
Alpha + beta = -k
Product of zeroes = c/a
Alpha x beta = 45
In the given eq. x2+kx+45 in the form of ax2 + bx + c
We get a = 1, b= k and c = 45
Replacing values,
(-k/1)2 – 4* (45/1) = 144
=> k2 – 180 = 144
=> k2 = 324
=> k = 18
Hope it helps you!
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