If alpha and beta are the zeros of polynomial 2 x square - 11 x + 12 then find the polynomial whose zeros are 1 by Alpha and one by beta
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Answer:
8x² + 14 x + 3 = 0
Explanation:
2x² - 11x + 12 = 0
2x² - 8x -3x +12 = 0
2x(x - 4) -3(x - 4) = 0
(x - 4)(2x - 3)= 0
x = 4 or x = 3/2
Therefore, Alpha and Beta are 4 and 3/2
1/alpha and 1/beta = 1/4 and 3/2
polynomial ---> x² + (sum)x + product = 0
=> x² + 7/4 x + 3/8 = 0 (multiply by 8)
=> 8x² + 14x + 3 = 0 (final answer)
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