If alpha and beta are the zeros of polynomial p(x)=3x^2+2x+1,find the polynomial whose zeroes are 1-alpha/1+beta and 1- beta/1+beta
pls answer it fast pls....
time:9.08pm
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Answer:
(1+α)(1+β)
(1−α)(1−β)
(1+α+β=αβ)
(1−α−β+αβ)
(
1+(α+β)+αβ
1−(α+β)+αβ
)
⎣
⎢
⎢
⎡
1−
3
2
+
3
1
1+
3
2
+
3
1
⎦
⎥
⎥
⎤
[
2
2×3
]=3
=
(1+α+β+αβ)
(1−α)(1+β)+(1−β)(1+α)
=
3
2
1+β−α−αβ+1+α−β−αβ
=
2
3(2−2αβ)
=3(1−αβ)
=3(1−
3
1
)
=2
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