If alpha and beta are the zeros of polynomial then find the quadratic polynomial whose zeros are 2 alpha and 2 Beta
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the quadratic equation is
x^2 +7x + 10
we know that
quadratic equation are in the form of
ax^2+bx+c=0
then the
sum of zeros is = -b/a
product of zeros = c/a
after putting in the values you will get two equation in terms of alpha and beta
solve them you will get two values of alpha and beta
alpha= -5 or -2
beta= -5 or -2
then put the value of two alpha and two beta in this equation
x^2+(-(2*alpha + 2 beta)+(2alpha*2beta)
hope this is the answer
x^2 +7x + 10
we know that
quadratic equation are in the form of
ax^2+bx+c=0
then the
sum of zeros is = -b/a
product of zeros = c/a
after putting in the values you will get two equation in terms of alpha and beta
solve them you will get two values of alpha and beta
alpha= -5 or -2
beta= -5 or -2
then put the value of two alpha and two beta in this equation
x^2+(-(2*alpha + 2 beta)+(2alpha*2beta)
hope this is the answer
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